Java program to find second largest number in an array

This example shows you how to find the second largest number in an array of java

Step 1:

    Iterate the given array

Step 2 (first if condition arr[i] > largest):

    If current array value is greater than largest value then

        Move the largest value to secondLargest and make

        current value as largest

Step 3 (second if condition arr[i] > secondLargest )  

 If the current value is smaller than largest and greater than secondLargest  then the current value becomes secondLargest

Program

public class SecondLargest {
 
	public static void main(String[] args) {
 
		int arr[] = { 14, 46, 47, 86, 92, 52, 48, 36, 66, 85 };
		int largest = arr[0];
		int secondLargest = arr[0];
		
		System.out.println("The given array is:" );
		for (int i = 0; i < arr.length; i++) {
			System.out.print(arr[i]+"\t");
		}
		for (int i = 0; i < arr.length; i++) {
 
			if (arr[i] > largest) {
				secondLargest = largest;
				largest = arr[i];
 
			} else if (arr[i] > secondLargest) {
				secondLargest = arr[i];
 
			}
		}
 
		System.out.println("\nSecond largest number is:" + secondLargest);
 
	}
}

Output

The given array is:

14 46 47 86 92 52 48 36 66 85

Second largest number is:86